How to lay out the answer. Follow the frame, then write it in your own words.
1 · Open in two lines. The rate (velocity) of an enzyme reaction depends on several factors. Each is studied by changing one factor while keeping the others constant.
2 · Draw the graphs. [Graphs: hyperbola for substrate with Vmax and Km marked; straight line for enzyme; bell-shaped curves for temperature and pH]
3 · Substrate and enzyme concentration.
Substrate: rate rises, then levels off at Vmax. Km = substrate level at ½ Vmax.
Enzyme: rate rises in direct proportion when substrate is in excess.
4 · Temperature and pH.
Temperature: optimum about 37 °C; high heat denatures the enzyme.
pH: each enzyme has its own optimum (pepsin about 2, trypsin about 8).